Panthera's Puzzle Contest Birthdays

Birthdays

To be listed on this page, you MUST submit a puzzle with your birthdate in it AND email panth@puzzleu.com to make sure I remember to include you!

Amy Galitzer
My birthday month is x^2^2 and the day is y^2^2. 0 panth@puzzleu.com
Denis Borris
In a non-leap year, my birthday's julian date (j)^M
(Feb 3 = 34) divided the month number (m) (Feb 3 = 2)^M
is equal to m + the day number (d) (Feb 3 = 3).^M
In other words, j / m = m + d^M
And it just happens that my d is the lowest possible.
borrisd@magi.com
Sudipta Das
Suppose my birthdate is mm-dd-yyyy ( month-day-year). If you take 2 digits out of these 8 digits and add them up , you will get 1,2,3,4,8,9,10,11,16 and 17 as the sums.(For example, if my birthdate had been 06-23-1975 , then you would have got 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15 and 16 as the sums) Further , dd can be expressed as the difference of the squares of two different positive integers in two different ways. I was born in a non-leap year in the 20th century.
sudiptadas786@rediffmail.com
Daniel Mondot
Two holidays have the same numerical value.^M&^M&My birthday is one day before o ne of them (the first one).
danmondot@yahoo.com
Gary Clemens
On my birthday, the number of days (D) remaining in a^M &non-leap year is palindromic in both base 2 (binary)^M&and 16 (hex). This numb er is not prime, but the difference^M&between my birthday's Julian representatio n and this number^M&is! Also, on my next birthday, the difference between my^M& birth year (yy) and this number was my age ten years ago.^M&D is at a maximum.
gclemens@alsysinc.com