Four people (Jesse, Ken, Pamela, and Opie) with last names Maciejewski, Valdez, Harris, and Regoli, each owned a number of chocolate bars.
Each person was of a different occupation: graphic artist, xylophone player, janitor, and optometrist.
If each person owned one of the following amounts of chocolate bars, (6, 11, 9, and 15) can you figure out the first name, last name, and how many chocolate bars each person owned?
Valdez owned less chocolate bars than the janitor, and more than Jesse.
Opie, the person who owned 6 chocolate bars, and the janitor go shopping together on Saturdays.
Opie and Regoli once dated the graphic artist.
The optometrist isn't Opie Maciejewski.
The person who owned 9 chocolate bars, Maciejewski, and the optometrist have known each other for years.
The person who owned 11 chocolate bars lives in the same building as Maciejewski and Jesse.
Pamela and Harris once dated the xylophone player.
Opie, and Regoli often watch fights at the optometrist's place.
The person who owned 6 chocolate bars lives in the same building as Maciejewski and Pamela.
Regoli owned more chocolate bars than the optometrist, and more than Pamela.
Valdez wasn't the person who owned 15 chocolate bars. Neither did Ken nor the optometrist.
Jesse, Maciejewski, and the person who owned 11 chocolate bars each had different dinners last night.
The graphic artist isn't Opie or the person who owned 6 chocolate bars.
Pamela is not the person who owned 15 chocolate bars, nor has the last name Harris.
Valdez and Jesse aren't the person who owned 11 chocolate bars.
Maciejewski and Ken aren't the person who owned 9 chocolate bars.
Pamela is not the person who owned 6 chocolate bars, nor has the last name Maciejewski.
The xylophone player isn't Jesse Harris.
The optometrist, the person who owned 6 chocolate bars, didn't want a copy of Maciejewski's book.
The optometrist, whose first name is Jesse, wasn't the person who owned 15 chocolate bars.
Mac
Val
Har
Reg
gra
xyl
jan
opt
6
11
9
15
Jes
Ken
Pam
Opi
6
11
9
15
gra
xyl
jan
opt
Place a N in any square that is a definite "no" and a Y in any square that is a definite "yes". I give up!