Four people (Ken, Amy, Pamela, and Jesse) with last names Harris, Borris, Xevarone, and O'Neal, each gave a number of dogs.
Each person was of a different occupation: banker, coat check person, quack, and mathematician.
If each person gave one of the following amounts of dogs, (7, 5, 25, and 19) can you figure out the first name, last name, and how many dogs each person gave?
Borris isn't the quack or the person who gave 19 dogs.
Harris and Ken aren't the person who gave 7 dogs.
The quack isn't Ken Borris.
Ken, and O'Neal often watch fights at the coat check person's place.
The banker, who gave 19 dogs, isn't Borris.
The mathematician isn't Amy O'Neal.
The person who gave 25 dogs lives in the same building as Xevarone and Amy.
The person who gave 25 dogs is not named Amy or Xevarone.
O'Neal and Ken aren't the person who gave 5 dogs.
Pamela, Borris, and Amy were not the person who gave 5 dogs.
Amy is not the person who gave 25 dogs, nor has the last name Harris.
The person who gave 7 dogs, O'Neal and Ken all went to the The coat check person, who gave 7 dogs, isn't Harris.
The coat check person, who gave 7 dogs, isn't Harris.
The mathematician, who gave 25 dogs, isn't Xevarone.
The mathematician, whose first name is Ken, wasn't the person who gave 7 dogs.
Har
Bor
Xev
O'N
ban
coa
qua
mat
7
5
25
19
Ken
Amy
Pam
Jes
7
5
25
19
ban
coa
qua
mat
Place a N in any square that is a definite "no" and a Y in any square that is a definite "yes". I give up!