Four people (Jesse, Ivan, Y.C., and Harriett) with last names Borris, Iverson, Galitzer, and Xevarone, each owned a number of puzzles.
Each person was of a different occupation: horse trainer, delivery person, valet, and salesman.
If each person owned one of the following amounts of puzzles, (14, 15, 16, and 6) can you figure out the first name, last name, and how many puzzles each person owned?
Harriett, who is not Galitzer, is the salesman's cousin.
The salesman, whose first name is Jesse, wasn't the person who owned 14 puzzles.
Xevarone wasn't the person who owned 15 puzzles. Neither did Y.C. nor the horse trainer.
The person who owned 15 puzzles lives in the same building as Galitzer and Harriett.
Harriett, Galitzer, and Jesse were not the person who owned 15 puzzles.
The valet, who owned 16 puzzles, isn't Xevarone.
Jesse, the person who owned 15 puzzles, and the horse trainer go shopping together on Saturdays.
The salesman, the person who owned 6 puzzles, didn't want a copy of Iverson's book.
The horse trainer isn't Jesse Xevarone.
Bor
Ive
Gal
Xev
hor
del
val
sal
14
15
16
6
Jes
Iva
Y.C
Har
14
15
16
6
hor
del
val
sal
Place a N in any square that is a definite "no" and a Y in any square that is a definite "yes". I give up!